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trigonometry - Proving that $\tan \theta=\cot(90^\circ-\theta)$ when $\theta>90^\circ$ - Mathematics Stack Exchange

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I'm asked to prove $\tan \theta=\cot (90-\theta)$ So $\tan \theta =\frac{a}{b}=\cot(90^\circ-\theta)$ But what if $\theta>90?$

$trigonometry - Proving that $\tan \theta=\cot(90^\circ-\theta)$ when $\theta>90^\circ$ - Mathematics Stack Exchange$

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$trigonometry - Proving that $\tan \theta=\cot(90^\circ-\theta)$ when $\theta>90^\circ$ - Mathematics Stack Exchange$

trigonometry - Why can the trigonometric functions be interpreted

$trigonometry - Proving that $\tan \theta=\cot(90^\circ-\theta)$ when $\theta>90^\circ$ - Mathematics Stack Exchange$

Prove that ( : frac { cot left( 90 ^ { circ } - theta right

$trigonometry - Proving that $\tan \theta=\cot(90^\circ-\theta)$ when $\theta>90^\circ$ - Mathematics Stack Exchange$

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$trigonometry - Proving that $\tan \theta=\cot(90^\circ-\theta)$ when $\theta>90^\circ$ - Mathematics Stack Exchange$

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$trigonometry - Proving that $\tan \theta=\cot(90^\circ-\theta)$ when $\theta>90^\circ$ - Mathematics Stack Exchange$

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$trigonometry - Proving that $\tan \theta=\cot(90^\circ-\theta)$ when $\theta>90^\circ$ - Mathematics Stack Exchange$

Prove that: (((cosec(90° + x) + cot(450° + x))/(cosec(90° - x) + tan(180° - x))) + ((tan(180° + x) + sec(180° - x))/(tan(360° + x) - sec(-x)))) = 2 - Sarthaks eConnect

$trigonometry - Proving that $\tan \theta=\cot(90^\circ-\theta)$ when $\theta>90^\circ$ - Mathematics Stack Exchange$

⏩SOLVED:Given secθ=3, use trigonometric identities to find the